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Helium nuclei combine to form an oxygen nucleus. The energy released in the reaction is if `m_(O)=15.9994 "amu"` and `m_(He)=4.0026 "amu"`A. `10.24 Me V`B. `0 Me V`C. `5.24 Me V`D. `4 Me V` |
Answer» Correct Answer - A `Deltam= 4m_(He)-m_(0)` `Deltam= 0.01 "amu" " " DeltaE=DeltaMC^(2)=0` binding energy per`//`Nucleon`=176//16"amu"=10.24 meV` |
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