1.

Helium nuclei combine to form an oxygen nucleus. The energy released in the reaction is if `m_(O)=15.9994 "amu"` and `m_(He)=4.0026 "amu"`A. `10.24 Me V`B. `0 Me V`C. `5.24 Me V`D. `4 Me V`

Answer» Correct Answer - A
`Deltam= 4m_(He)-m_(0)`
`Deltam= 0.01 "amu" " " DeltaE=DeltaMC^(2)=0`
binding energy per`//`Nucleon`=176//16"amu"=10.24 meV`


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