1.

‘Henry’s Law is special case of Raoult’s Law. Explain how? 

Answer»

 According to Raoult’s Law- P1 = P1 χ 1

According to Henry’s Law- P = Kχ g As vapour pressure of liquid increases with increase in mole fraction of it in solution as mole fraction of gas in solution increases with increase in pressure of the gas. In this condition KH can be taken equivalent to P1 .



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