InterviewSolution
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InterviewSolution
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How can three resistor of resistances 2 Omega, 3 Omegaand 6 Omegabe connected to give a total resistance of 4 Omega |
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Answer» Solution : In order to obtain a total resistance of `4 Omega` from three resistors of `2 Omega, 3Omega and 6 Omega… to` First connect the two resistors of `3Omega and 6 Omega` in PARALLEL to get a total resistance of `2Omega`. This is because in parallel combination, `1/R_p = 1/R_1 + 1/R_2` `R_p=(R_1 R_2)/(R_1 +R_2)` `= (3 xx 6)/(3 + 6)` `=2 Omega`  Now, above parallel combination of `3Omega and 6 Omega` resistors is connected in series with the resmaining `2 Omega`resistor to get total resistance of `4 Omega`. This is because in series combination. `R_s =R_p +R_3` `=2 + 2` `= 4Omega` HENCE, the ARRANGEMENT of three resistors `2Omega, 3Omega and 6 Omega` which gives total resistance `4 Omega` can be represented as FOLLOWS : 
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