1.

How ethanoic acid reacts with following ? Give chemical equation :(a) Na_(2)CO_(3) (b) NaOH (c ) CH_(3)CH_(2)OH in presence of acid.

Answer»

Solution :(a) Ethanoic acid reacts with `Na_(2)CO_(2)` to FORM sodium ethanoate, `CO_(2)`and water.
`UNDERSET("Ethanoate Acid")(CH_(3)COOH) + Na_(2)CO_(3) rarr underset("Sodium ethanoate")(CH_(3)COONA) + CO_(2) + H_(2)O`
(b) Ethanoic acid reacts with NAOH to give sodium ethanoate and water.
`underset("Ethanoate Acid")(CH_(3)COOH) + NaOH rarr underset("Sodium ethanoate")(CH_(3)COONa) + H_(2)O`
(c ) Ethanoic acid react with `CH_(3)CH_(2)OH` in the presence of acid to give ester (Ethyl ethanoate) and water.
`underset("Ethanoate Acid")(CH_(3)COOH) + underset("Ethanol")(CH_(3)CH_(2)OH) OVERSET("Acid")rarr underset("Ethylethanoate")(CH_(3)COOCH_(2)CH_(3)) +H_(2)O`


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