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How far away from the surface of earth does the acceleration due to gravity become 36% of its value on the surface of earth? Radius of earth =6400km. |
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Answer» SOLUTION :`g'=36%" of "g= (36)/(100)g` `(36)/(100)g= g[(R )/(R+h)]^(2)` `(6)/(10)=(R)/(R+h)` `h=4/6R= 4267 km`. |
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