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How fast should a man weighing 600 N run so that his kinetic energy is 750 J ?( g=10 m s^(-2))

Answer»

Solution :Given :W=600 N ,g =10 m `s^(-2)`,
KINETIC energy =750 J,v=? Since W=MG `therefore600=mxx10` or m =60 mg
Kinetic energy =`(1)/(2)mv^(2)`
`750=(1)/(2)xx60xxv^(2)`
`therefore v^(2)=(2xx750)/(60)XXV^(2)`
`therefore v^(2)=(2xx750)/(60)=25`
or `v=sqrt(25)=5ms^(-1)`


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