1.

How high does the mercury barometer stand on a day when atmospheric pressure is 98.6 kPa ?

Answer»

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Solution :`H = P_("ATM")/P_(Hg) = 98.6 XX 10 xx 10 xx 10 `
` = ((N//m)^(2))/(13.6 xx 10 xx 10 xx 10 Kg//m^(3))`
` = 9.8 m//s^(2) = 740 MM`


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