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How many `alpha`-and `beta`-particle will be emitted when `._(98)Th^(234)` change into `._(84)Po^(218)`? |
Answer» `underset("Parent")(._(90)Th^(234) rarr ._(84)Po^(218)` Decrease in mass `= (234 - 218) = 16` Mass of 1 `alpha-"particle" `= 4 amu Therefore, number of `alpha`-particles emitted Number of `beta`-emitted - (Atomic number `= 2 xx` Number of `beta`-particles - Atomic number of end product) `2 xx 4 - (90 - 84) (8 - 6) = 2` Hence, number of `alpha`-particles = 4 and number of `beta`-particles = 2 |
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