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How many chlorine atoms can you ionize in the process `Cl rarr Cl^+ + e`, by the energy liberated from the following process ? `Cl + e^- rarr Cl^(-) for 6 xx 10^23 "atoms"` Given electron affinity ofm `Cl = 3.61 eV`, and `I P` of `Cl = 17.422 eV`.A. `1.24 xx 10^23 "atoms"`B. `9.82 xx 10^20 "atoms"`C. `2.02 xx 10^15 "atoms"`D. none of these |
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Answer» Correct Answer - A (a) Energy released in conversion of `6 xx 10^23 "atoms"` os `Cl^(-) ions` =`6 xx 10^23 xx "electron affinity"`, =`6 xx 10^23 xx 3.61` =`2.166 xx 10^24 eV` Let `x Cl` atoms are converted to `Cl^+` ion Energy absorbed `= x xx "ionization energy"` `x xx 17.422 = 2.166 xx 10^24` `x = 1.243 xx 10^23 "atoms"`. |
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