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    				| 1. | How many electrons per second pass through a section of wire carrying a current of `0.7A`? | 
| Answer» We known that `I = (q)/(t) = ("ne")/(t) , therefore, n = (it)/(e ) = (0.7xx1)/(1.6x10^(-19)` So number of electrons in `n = 0.44xx10^(19)` | |