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How many grams of a dibasic acid (mol. Mass `200`) should be present in `100 mL` of the aqueous solution to give `0.1 N` solution.A. 1 gB. 2 gC. 10 gD. 20 g |
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Answer» Correct Answer - A Equivalent weight of dibasic acid `=("Molecular weight")/(2)` `E=(200)/(2)=100` Stremgth `=0.1N, m = ? V = 100 mL` Normality (N) `=("Mass")/(E )xx(1000)/(V(L))` `w=(E NV)/(1000)=(100xx100xx0.1)/(1000)=1g` |
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