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How many grams of methanol would have to be added to water to prepare 150mL of solution which is `2M CH_(3)OH`?A. `9.6`B. `2.4`C. `9.6 xx 10^(3)`D. `4.3 xx 10^(2)` |
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Answer» Correct Answer - A `1000 mL` of `1M CH_(3)OH` requires methanol = 32 g `150mL` of `2M CH_(3)OH` requires mathanol `= (32)/(1000) xx 150 xx 2 = 9.6g` |
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