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How many moles of sodium chloride present in 250 mL of a 0.50 M NaCl solution ?A. 7.32 gB. 3.8 gC. 5 gD. 0.5 g

Answer» Correct Answer - C
No. of moles of NaOH =`(MxxV)/1000=(0.5xx250)/1000`=0.125
Mass of NaOH= 40 x 0.125 = 5 g


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