How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaC

1.	How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaCl` ?
Answer» Number of moles of `NaCl = (MV)/(1000)` `= (0.5 xx 50)/(1000)=0.025` `NaCl rarr Na^(+) +Cl^(-)` Number of moles of `Na^(+)=` Number of moles of NaCl `= 0.025` Number of ions of `Na^(+)=0.025 xx 6.023 xx 10^(23)` `= 1.505 xx 10^(22)`.

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How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaCl` ?

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