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How many resistors of 88 Omega are connected in parallel to carry 10 A current on a 220 V line ?

Answer»

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SOLUTION :Let n number of resistances are connected in parallel.
Equivalent resistance `, (1)/(R_(P)) = (n)/(88)`
`R_(p) = (88)/(n)`
V = IR or R` = (V)/(I)`
`(88)/(n) = (220)/(10)`
`n = (88) /(22)` = 4 resistors


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