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How many resistors of 88 Omega are connected in parallel to carry 10 A current on a 220 V line ? |
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Answer» <P> SOLUTION :Let n number of resistances are connected in parallel.Equivalent resistance `, (1)/(R_(P)) = (n)/(88)` `R_(p) = (88)/(n)` V = IR or R` = (V)/(I)` `(88)/(n) = (220)/(10)` `n = (88) /(22)` = 4 resistors |
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