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How many times will the rate of the elementary reaction 3X + Y → X2Y change if the concentration of the substance X is doubled and that of Y is halved?(a) r2= 4.5r1(b) r2= 5r1(c) r2= 2r1(d) r2= 4r1I got this question in an internship interview.This is a very interesting question from Rate of a Chemical Reaction in division Chemical Kinetics of Chemistry – Class 12

Answer»

The CORRECT choice is (d) r2= 4r1

Easiest explanation: Since it is an elementary reaction, its RATE law R1= k [A] ^3[B]

When the concentrations are CHANGED the new rate will be r2= k (2[A])^3([B]/2) = 4k[A]^3[B]

So, r2=4r1.



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