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How much ethyl alcohol must be added to `1.00 L` of water so that the solution will not freeze at `-4^(@)F` ?A. `122`gB. `512`gC. `670`gD. `495`g |
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Answer» Correct Answer - C `-4^(@)f`is to be converted into `C^(@)` `(F-32)/(180)=(C)/(100)` ltbr `(-6-30)/(180)=C/(100)` `:. C=-27^(@)C` `:. DeltaT_(f)=-27^(@)C` 1 L `H_(2)O=1000g` water `DeltaT_(f)=(1000k_(f)w_(1))/(m_(1)w_(1))` `w_(1)("ethyl alcohol")=(DeltaT_(f)m_(1)w_(2))/(1000k_(f))=(27xx46xx1000)/(1000xx1.86)` `=(12466)/(186)=670g` |
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