1.

How much heat should be supplied to convert ice of mass 50 g at 0^@C into water at 40^@ C ?

Answer»


Solution :Given :Mass of ice/WATER (m)=50 g
Change in temperature `(DELTA T)`
`= 40-0-40 ^@C`
We KNOW that: Latent heat of melting of ice `=L=("melt")=80 cal//g` ,Specific heat of water `C_("w")=1 cal//g^@C`
To find, Heat supplied (Q)
Formulae: i Heat required to CONVENT ice at `0^@C` into water at `0^@C " is " Q_1=mL_("melt")`
ii. Heat required to raise temperature of water from `0^@C`to `40^@C` is
`Q_2= mxxC_w xx Delta T`
Calculation: From formula (i),
`Q_1=50 xx 1 xx (40-0)=2000` cal TOTAL heat energy required
`Q=Q_1+Q_2`
`=4000 +2000=6000 cal`


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