1.

How much `K_(2)Cr_(2)O_(7) (M.W. = 294.19)` is required to prepare one litre of `0.1N` solution?A. `9.8063g`B. `7.3548g`C. `3.6774g`D. `4.903g`

Answer» Correct Answer - D
`Cr_(2)O_(7)^(2-) + 14H^(+) +6e^(-) rarr 2Cr^(3+) +7H_(2)O`
Eq. mass of `K_(2)Cr_(2)O_(7) = ("Mol. mass")/(6) = (294.19)/(6)`
`=49.03`
Mass of `K_(2)Cr_(2)O_(7)` required to prepare 1L of `0.1N K_(2)Cr_(2)O_(7)` solution `= 4.903g`


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