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How much momentum will a dumbbell of mass 10 kg transfer to the floor if it falls from a height of 80 cm ? Take its downward acceleration to be 10 ms^(-2). |
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Answer» SOLUTION :Mass of the dumbbell m =10 kg Distance covered by the dumbbell , s=80 cm =0.8 m Acceleration in the downward direction `a=10 m//s^2` Initial velocity of the dumbbell,u=o FINAL velocity of the dumbbell (when it was about to hit the floor) =v According to the third equatons of motion `v^2=u^2+2as` `v^2=0=2(10)0.8` v=4 m/s HENCE themomentum with which the dumbbell hits the floor is `=mv =10xx4 =40 kg ms^(-1)` |
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