InterviewSolution
Saved Bookmarks
| 1. |
Hydrogen atom in its ground state is excited by means of monochromatic radiation of wavelength `975A^(@)`. How many different lines are possible in the resulting spectrum? Calculate the longest wavelength amongst them. |
|
Answer» Correct Answer - six, `18800A^(@)` `lambda=975Å` `E=(lambdac)/(lambda)=(6.626xx10^(-34)xx3xx10^(8))/(975xx10^(10))=2.03xx10^(-18)J=12.75eV` So electron will excite to 4th energy level and when comeback number of emission line will be 6. minimum energy emitted `=E_(4)-E_(3)=0.66eV` `lambda=(hc)/(E)=(1.9878xx10^(-25))/(66xx1.6xx10^(-19))=1.882xx10^(-6)m=18820Å` |
|