1.

(i) Calculate the mass of 6.023 xx 10^(20) molecules of H_2O. (ii) Calculate the moles of 12g of magnesium. (iii) Calculate the number of molecules present in 50 g of Fe.

Answer»

Solution :Molecular mass of `H_2O = H XX 2 + O xx 1`
`= 1 xx 2 + 16 xx 1`
`= 2 + 16 = 18`
Mass of an ATOM = `("Number of atoms")/("Avagardo.s number") xx "mass of" H_2O`
`= (6.023 xx 10^(20))/(6.023 xx 10^(23)) xx 18`
`10^(-3) xx 18`
Mass of an atom = 0.018 g
(II) Number of moles = `("Given mass")/("molecular mass")`
`= 12/24 = 1/2 = 0.5`
`:. 12 g` MAGNESIUM makes 0.5 moles.
(iii) Number of atoms = `("Avagadro number" xx " Given mass)/("Gram atomic mass")`
`=(6.023 xx 10^(23) xx 50)/(55.9)`
`= 5.387 xx 10^(23)`
`:. 50 g Fe` contain `5.387 xx 10^(23)` atoms/molecules.


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