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(i)Calculate the number of moles in 12.046xx10^23 atom of copper. |
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Answer» Solution :`12.046xx10^23` atoms of copper `6.023xx10^23` atoms of copper =1 mole `therefore 12.046xx10^23` atoms of copper =`(1xx12.046xx10^23)/(6.023xx10^23)`=2 moles of copper (ii) No. of moles=`"Mass"/"MOLAR mass"` Mass=No. of moles X molar mass Molar mass of `H_2O` = (2 x 1) +16 =18 Mass =2 x 18 =36 g (iii) Formula of magnesium sulphide =MgS Ratio of mass Mg and S =3:4 NUMBER of atoms in 3g of Mg = `N_A/24 xx3 =N_A/8` Number of atoms in 4g of S =`N_A/32xx4 =N_A/8` `therefore` Ratio of the number of Mg and S =`N_A/8:N_A/8` =1:1 |
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