(i) Draw a schematic diagram of a circuit consisting of a battery of five 2V cells, a5 Omega resistor, a10 Omega resistor and a 15 Omega resistor and a plug key all connected in series. (ii) Calculate the electric current passing through the above circuit when the key is closed. (iii) Potential difference across 15 Omega resistor.

(i) Draw a schematic diagram of a circuit consisting of a battery of f

1.	(i) Draw a schematic diagram of a circuit consisting of a battery of five 2V cells, a5 Omega resistor, a10 Omega resistor and a 15 Omega resistor and a plug key all connected in series. (ii) Calculate the electric current passing through the above circuit when the key is closed. (iii) Potential difference across 15 Omega resistor.
Answer» Solution :(i) The SCHEMATIC diagram is GIVEN in Fig.12.34. (ii) Here total voltage `V= 5 times 2=10V` and total resistance `R=R_1+R_2+R_3` `=5+10+15=30 Omega` `THEREFORE` Current PASSING through the circuit when the key is closed. `I=V/R=(10V)/(30 Omega)=1/3 A=0.33A` (iii) Potential difference across resistor `R_3` of `15 Omega` `V_3=IR_3=1/3 times 15=5V`