1.

(i) Establish that g(x) =1 – x + |x| is continuous at origin.(ii) Check whether h(x) = |l – x + |x|| is continuous at origin.

Answer»

(i) Given; g(x) = 1 – x + |x| ⇒ g(x) (1 – x) + |x|

Here g(x) is the sum of two functions continuous functions hence continuous.

(ii) We have;

fog(x) = f(gx))

= f(1-x+|x|) = |1-x-|x|| = h(x)

The composition of two continuous functions is again continuous. Therefore h(x) continuous.



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