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(i) Establish that g(x) =1 – x + |x| is continuous at origin.(ii) Check whether h(x) = |l – x + |x|| is continuous at origin. |
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Answer» (i) Given; g(x) = 1 – x + |x| ⇒ g(x) (1 – x) + |x| Here g(x) is the sum of two functions continuous functions hence continuous. (ii) We have; fog(x) = f(gx)) = f(1-x+|x|) = |1-x-|x|| = h(x) The composition of two continuous functions is again continuous. Therefore h(x) continuous. |
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