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If \(f(x) =\begin{cases}x\,sin \frac{1}{x}, & \quad x\neq 0\\k, & \quad x=0\end{cases}\) is continuous at x = 0, then the value of k =f(x) = {x sin(1/x), x ≠ 0, k, x = 0 is continuous at x = 0, then the value of k(A) 1(B) –1(C) 0(D) 2 |
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Answer» Correct answer is (C) 0 |
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