I started on my bicycle at 7 A.M. to reach a certain place. After goin

1.	I started on my bicycle at 7 A.M. to reach a certain place. After going a certain distance my bicycle went out of order. Consequently I rested for 35 minutes and came back to my house walking all the way. I reached my house at 1 P.M. If my cycling speed is 10 km/hr and my walking speed is 1 km/hr, then what distance did I cover on my bicycle?
Answer» Let the distance covered on the bicycle was x km. Then, \(\frac{x}{10}+\frac{35}{60}+x=6\,hrs\) ⇒ \(\frac{6x+35+60x}{60}\) = 6 ⇒ 66x + 35 = 360 ⇒ 66x = 325 ⇒ x = \(\frac{325}{66}\) km = \(4\frac{61}{66}\) km.

I started on my bicycle at 7 A.M. to reach a certain place. After going a certain distance my bicycle went out of order. Consequently I rested for 35 minutes and came back to my house walking all the way. I reached my house at 1 P.M. If my cycling speed is 10 km/hr and my walking speed is 1 km/hr, then what distance did I cover on my bicycle?

Answer»

Let the distance covered on the bicycle was x km. Then,

\(\frac{x}{10}+\frac{35}{60}+x=6\,hrs\) ⇒ \(\frac{6x+35+60x}{60}\) = 6 ⇒ 66x + 35 = 360

⇒ 66x = 325 ⇒ x = \(\frac{325}{66}\) km = \(4\frac{61}{66}\) km.

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