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(i) What is the energy and wavelenght of phpotons of frequncey 3.4MHz? (ii) Also calculate the energy per mole of photons of the same wavelength. |
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Answer» `v=3.4MHz=3.4xx10^(6)HZ=3.4xx10^(6)s^(-1).` `lambda=(c)/v=(3xx10^(8)ms^(-1))/(3.4xx10^(6)s^(-1))`=88.2m Energy, `E=hv=6.626xx10^(-34)xx3.4xx10^(6)J` =`2.253xx10^(-27)J` Enegry per mole of photon = `6.02xx10^(23)xx2.53xx10^(-27)J mol^(-1)` `=1.356xx10^(-3) J mol^(-1)` |
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