1.

Identify the substances that are oxidised and the substances that are reduced in the reaction : CuO(s)+ H_(2)(g) to Cu(s)+H_(2)O(I)

Answer»

Solution :`CUO(s)+ H_(2)(G) to CU(s)+H_(2)O(I)`
In this reaction, CuO is reduced to Cu, while `H_(2)` is oxidised to `H_(2)O`


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