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If `1+sinx+sin^2x+sin^3x+oo`is equal to `4+2sqrt(3),0ltxltpi,` then `x`is equal to |
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Answer» `1+sinx+sin^2x+sin^3x+...oo = 4+2sqrt3` `=>1/(1-sinx) = 4+2sqrt3` `=>1-sinx = 1/(4+2sqrt3)**(4-2sqrt3)/(4-2sqrt3)` `=>1-sinx = (4-2sqrt3)/(16-12) = (4-2sqrt3)/4` `=>1-sinx = 1-sqrt3/2` `=>sinx = sqrt3/2` `:. x = pi/3 or (2pi)/3.` |
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