If `10%` of a radioactive material decays in `5` days, then the amount of original material left after `20` days is approximately.A. 0.6B. 0.65C. 0.7D. 0.75

If `10%` of a radioactive material decays in `5` days, then the amount

1.	If `10%` of a radioactive material decays in `5` days, then the amount of original material left after `20` days is approximately.A. 0.6B. 0.65C. 0.7D. 0.75
Answer» Correct Answer - B (b) Disintegrating percentage `= 10` Surviving percentage `= 100 - 10 = 90` Surviving fraction `=f` `f = (90)/(100) = 0.9` `t_f = 5 days t = 20 days` `n_f = (t)/(t_f) = (20)/(5)= 4` `(N)/(N_0) = (f)^(n_f) = (0.9)^4` ` :. ((N)/(N_0)) xx 100 = 0.6560 + 100` `=65.6 %`.

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If `10%` of a radioactive material decays in `5` days, then the amount of original material left after `20` days is approximately.A. 0.6B. 0.65C. 0.7D. 0.75

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