1.

If `10gm` of an unknown substance (non-electrolytic) is dissolved to make `500mL` of solution, then osmotic pressure at `300K` is observed to be `1.23` atm find molecular weight?

Answer» `1.23=(10xx1000)/(Mxx500)xx0.082xx300`
`M=(20)/(1.23)xx(0.082)/(100)xx300 approx400gm//"mol"`


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