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If `|(12x)/(4x^(2)+9)| le 1`, thenA. `x in R`B. `x in [-3,3]`C. `x in [-1,oo)`D. `x in (-oo,2]`

Answer» Correct Answer - A
`(a)` `|(12x)/(4x^(2)+9)| le 1`
`-1 le (12x)/(4x^(2)+9) le 1`
Since `4x^(2)+(9)` is postive for all real `x`, we can multiply by `4x^(2)+9`
`:. -(4x^(2)+(9)) le 12x le (4x^(2)+(9))`
`(2x+3)^(2) ge 0` and `(2x-3)^(2) ge 0`
Above is true for all real values of `x`.


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