1.

The solution of `|2x-3| lt |x+2|` isA. `(-oo,1//3)`B. `(1//3,5)`C. `(5,oo)`D. `(-oo,1//3) uu (5,oo)`

Answer» Correct Answer - B
`(b)` `|2x-3| lt |x+2|`
Squaring both sides
`(2x-3)^(2)-(x+2)^(2) lt 0`
`(x-5)(3x-1) lt 0`
`implies x in ((1)/(3),5)`


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