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If `200 MeV` energy is released in the fission of a single `U^235` nucleus, the number of fissions required per second to produce `1` kilowatt power shall be (Given `1 eV = 1.6 xx 10^-19 J`).A. `3.125xx10^(13)`B. `3.125xx10^(14)`C. `3.125xx10^(15)`D. `3.125xx10^(16)` |
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Answer» Correct Answer - A |
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