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If `(3pi)/4ltalphaltpi," then "sqrt(2cotalpha+1/sin^2alpha)`is equal toA. `1+cotalpha`B. `-1-cotalpha`C. `1-cotalpha`D. `-1+cotalpha` |
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Answer» Correct Answer - B `sqrt(2cotalpha+1/sin^2alpha)=sqrt(2cot alpha+cosec^2alpha)` `=sqrt(2cotalpha+1+cot^2alpha)` `=abs(1+cotalpha)=-1-cotalpha` [Since `aotalphalt-1" when "3pi//4ltalphaltpi`] |
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