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If 4/5 ,a and 2 are three consecutive terms of an A.P, then find the value of a |
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Answer» D = a - 4/5 =2- aD = a+a = 2+4/5D = 2a = 10+4/5D = 2a = 14/5 D = a = 14/10Therefore the answer is @4/10 a=7/5.... A=7/5 a = 14/10 |
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