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If `5.85`g of `NaCl`are dissolved in`90g` of water,the moles fraction of`NaCl` isA. `0.1`B. `0.2`C. `0.3`D. `0.0196` |
Answer» Correct Answer - D `5.85gNaCl=(5.85)/(58.5)"mole" =0.1mol` `90 gH_(2)O=(90)/(18)"moles" =5"moles"` Mole fraction of `NaCl =(0.1)/(5+0.1)~~0.0196` |
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