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If 5 students are transferred from B to A, what will be the minimum possible average of A?1). 20.692). 213). 20.754). 20.6 |
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Answer» Lowest score of B = 23 Present total MARKS of A = 20 × 20 = 400 Marks of 5 students of B = 23 × 5 = 115 New total marks of B = 400 + 115 = 515 New AVERAGE of B = $(\frac{{515}}{{25}} = 20.6)$ HENCE, 20.6 is the new minimum average of A. |
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