1.

If 5 students are transferred from B to A, what will be the minimum possible average of A?1). 20.692). 213). 20.754). 20.6

Answer»

Lowest score of B = 23

Present total MARKS of A = 20 × 20 = 400

Marks of 5 students of B = 23 × 5 = 115

New total marks of B = 400 + 115 = 515

New AVERAGE of B = $(\frac{{515}}{{25}} = 20.6)$

HENCE, 20.6 is the new minimum average of A.



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