W(n) = 100n + 1 Kg1). 301 kg2). 401 kg3). 501 kg4). 601 kg – InterviewSolution

InterviewSolution

1.

W(n) = 100n + 1 Kg1). 301 kg2). 401 kg3). 501 kg4). 601 kg

Answer»

Weight of FIRST vessel = W(1) = 100 × 1 + 1

∴ Sum of all weight’s = 100 × 1 + 1 + 100 × 2 + 1 + 100 × 3 + 1 + 100 × 4 + 1 + 100 × 5 + 1 = 100(1 + 2 + 3 + 4 + 5) + 1 × 5 = 100(5 × 6/2) + 5

∴ Average weight = (100 × (5 × 6/2) + 5)/5 = 100 × 6/2 + 1 = 301 Kg

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