1.

What is the maximum possible average achievable for group B?1). 252). 24.53). 25.54). 24

Answer»

Present AVERAGE of B = 25 × 25 = 625

Number of students transferred from A to B = 5

For maximum average B’s HIGHEST score students should get transferred = 22

Max score of A = 22

Max marks for 5 students in A = 22 × 5 = 110

New marks = 625 + 110 = 735

New number of students in Class B = 25 + 5 = 30

∴ Average number of marks of B = $(\FRAC{{735}}{{30}} = 24.5)$

∴ 24.5 is the maximum average achievable for GROUP B.



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