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InterviewSolution
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If 75% of a frist-order reaction is completed in 32 min, than 50% of the reaction would complete in? a. 24 min b. 16 min c. 8 min d. 4 minA. a. 24 minB. b. 16 minC. c. 8 minD. d. 4 min |
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Answer» Correct Answer - b. 16 min Use direct formula `(t_(x%))/(t_(y%)) = ("log" (a)/(a - x))/("log" (a)/(a - y))` `:. (t_(50%))/(t_(75%)) = ("log" (100)/(100 - 50))/("log" (100)/(100 - 75)) implies t_(50%) = (t_(75%))/(2)` `:.t_(32)/(2) = 16 "min"` |
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