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If 9 Men Working 7.5 Hours A Day Can Finish A Piece Of Work In 20 Days, Then How Many Days Will Be Taken By 12 Men, Working 6 Hours A Day To Finish The Work? It Is Being Given That 2 Men Of Latter Type Work As Much As 3 Men Of The Former Type?

Answer»

Work done by 9 men in a day = 1/20 

∴Work done by 1 man in a day for 7.5 hours = (1/20) ÷ 9 = 1/180 

∴ Work done by 1 man in an hour = (1/180) ÷ (7.5) = 1/1350 

Given that 2 men of latter TYPE are equal to 3 men of former type ⇒ 1 man of latter type = 1.5 men of former type. 

∴ Work done by 1 man of latter type in an hour = 1.5 × (1/1350) = 1/900 

∴ Work done by 1 man in 6 hours = 6 × (1/900) = 1/150 

∴ Work done by 12 men in a day working 6 hours/day = 12 × (1/150) = 2/25 

Days REQUIRED to finish the work = 25/2 = 12.5 days.

Work done by 9 men in a day = 1/20 

∴Work done by 1 man in a day for 7.5 hours = (1/20) ÷ 9 = 1/180 

∴ Work done by 1 man in an hour = (1/180) ÷ (7.5) = 1/1350 

Given that 2 men of latter type are equal to 3 men of former type ⇒ 1 man of latter type = 1.5 men of former type. 

∴ Work done by 1 man of latter type in an hour = 1.5 × (1/1350) = 1/900 

∴ Work done by 1 man in 6 hours = 6 × (1/900) = 1/150 

∴ Work done by 12 men in a day working 6 hours/day = 12 × (1/150) = 2/25 

Days required to finish the work = 25/2 = 12.5 days.



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