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If \(a = 124,\sqrt[3]{{a\left( {{a^2} + 3a + 3} \right) + 1}} = ?\)1). 52). 43). 1234). 125 |
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Answer» ⇒ Given: $(a = 124,)$ $(\RIGHTARROW \;\sqrt[3]{{a\LEFT( {{a^2} + 3a + 3} \right) + 1}} = ?)$ ⇒ We PUT the value of a in above equation $(\Rightarrow \sqrt[3]{{\;124\left( {{{124}^2} + \left( {3 \times 124} \right) + 3} \right) + 1}})$ $(\Rightarrow \sqrt[3]{{124\left( {15376 + 372 + 3} \right) + 1}})$ ⇒ 125 |
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