1.

If `a=9,b=4a n dc=8`then find the distance between the middle point of BC and the foot ofthe perpendicular form `Adot`

Answer» We can create a triangle `ABC` with the given details.
Please refer to video to see the diagram.
We have to find `DE`.
From the diagram,
`DE = CD - CE = a/2- bcosC`
`=>DE = a/2 - b((a^2+b^2-c^2)/(2ab))`
`=(a^2-a^2-b^2+c^2)/(2a)`
`=(-b^2+c^2)/(2a) = (-(4)^2 +(8)^2)/(2(9))``=48/18 = 8/3`
`:. DE = 8/3`


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