If a `._(92)U^(235)` nucleus upon being struck by a neutron changes to `._(56)Ba^(145)`, three neutrons and an unknown product. What is the unknown product?

If a `._(92)U^(235)` nucleus upon being struck by a neutron changes to

1.	If a `._(92)U^(235)` nucleus upon being struck by a neutron changes to `._(56)Ba^(145)`, three neutrons and an unknown product. What is the unknown product?
Answer» The reaction can be presented as: `._(92)U^(235) ._(0)n^(1) rarr ._(56)Ba^(145) + ._(Z)X^(A) + ._(0)n^(1)` Equating the mass number on both sides, we get `235 + 1 = 145 + A + 3 xx 1` `:. A = 88 =` Atomic mass of `X` Atom Similarly equating atomic numbers on both sides, we get `:. 92 + 0 = 56 + Z + 3 xx 0` `:. Z = 36 =` Atomic number of `X` Atoms Therefore, unknown product is `._(36)X^(88)`, i.e., `._(36)Kr^(88)`.

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If a `._(92)U^(235)` nucleus upon being struck by a neutron changes to `._(56)Ba^(145)`, three neutrons and an unknown product. What is the unknown product?

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