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If `A+B=90^(@)`, then the value of `sin^(2)A+sin^(2)B=`A. `-1`B. 0C. 1D. `(1)/(sqrt2)` |
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Answer» Correct Answer - C `A+B=90^(@)impliesB=90^(@)-A` Now, `sin^(2)+A+sin^(2)B` `=sin^(2)A+cos^(2)A=1` |
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