1.

If `sin 3A =cos(A-10^(@))` where 3A is an acute angle , then find the value of A.

Answer» `sin 3A=cos (A-10^@)`
`rArr (90^@-3A)=cos(A-10^@)[because sin theta =cos (90^@0theta)]`
` rArr 90^@-3A =A -10^@rArr 4A=100^@rArr A=25^@`.
Hence, `A=25^@`.


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