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If `sin 3A =cos(A-10^(@))` where 3A is an acute angle , then find the value of A. |
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Answer» `sin 3A=cos (A-10^@)` `rArr (90^@-3A)=cos(A-10^@)[because sin theta =cos (90^@0theta)]` ` rArr 90^@-3A =A -10^@rArr 4A=100^@rArr A=25^@`. Hence, `A=25^@`. |
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