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If `sec 5A=cosec (A-30^@)`, where 5A is an acute angle then find the value of A. |
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Answer» `sec 5A=cosec (A-30^@)` `rArr cosec (90^@-5A)=cosec(A-30^@) [because sec theta =cosec (90^@-theta)]` `rArr 90^@-5A =A-30^@rArr 6A=120^@rArr A =20^@`. Hence, `A=20^@`. |
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