1.

If `a+b+c=0,`one root of `|a-x c b c b-x a b a c-x|=0`is`x=1`b. `x=2`c. `x=a^2+b^2+c^2`d. `x=0`A. `x=1`B. `x=2`C. `x=a^(2)+b^(2)+c^(2)`D. `x=0`

Answer» Correct Answer - D
Operating `C_(1) to C_(1) +C_(2) +C_(3) `we get
`(a+b+c-x) |{:(1,,c,,b),(1,,b-x,,a),(1,,a,,c-x):}|=0`
`:. x=a+ b+c=0`


Discussion

No Comment Found